## Mean, Mode and Median

1. The following is a hypothetical list of exam scores. Calculate the mode, median, and mean, and discuss how these three scores compare to each other.

Grade

100

78

89

92

55

90

80

65

90

88

95

90

62

**Solution**

Mode

Mode = the most occurring value = 90

Median

Median = the middle number after arranging the value ascending or descending order

Median = 69

Mean

Mean= (∑▒x)/n=(100+78+89+92+55+90+80+65+90+88+95+90+62)/13

Mean=1074/13=82.6154

The mean is the average score of the student will the median is the 50% score of the student while the mode is the most occur scores of the student in the examination.

Hypothetical Frequency Distribution of Exam Scores.

a. Calculate the cumulative frequencies (Cf), proportions (Prop), percentages (Pctg), and cumulative percentages (Cpctg) and place them in the table (you can copy and paste the table into your answer box).

b. Calculate the mean of the distribution. Note: There are multiple frequencies for each score.

Grade | f | Cf | Prop | Pctg | Cpctg |

100 | 2 | 2 | 0.0377 | 3.77 | 3.77 |

93 | 2 | 4 | 0.0377 | 3.77 | 7.55 |

90 | 4 | 8 | 0.0755 | 7.55 | 15.09 |

88 | 3 | 11 | 0.0566 | 5.66 | 20.75 |

87 | 7 | 18 | 0.1321 | 13.21 | 33.96 |

85 | 6 | 24 | 0.1132 | 11.32 | 45.28 |

79 | 8 | 32 | 0.1509 | 15.09 | 60.38 |

76 | 5 | 37 | 0.0943 | 9.43 | 69.81 |

75 | 7 | 44 | 0.1321 | 13.21 | 83.02 |

65 | 9 | 53 | 0.1698 | 16.98 | 100.00 |

**N=53**

## Deviation Score

3. Compute deviation scores for each of the hypothetical grades listed below. What is the sum of the deviation scores? Note: Remember that you must first calculate the mean.

Grade (X-X ̅)

100 16.8

78 -5.2

89 5.8

92 8.8

55 -28.2

90 6.8

80 -3.2

65 -18.2

88 4.8

95 11.8

Mean= (∑▒x)/n=(100+78+89+92+55+90+80+65+88+95)/10

Mean= 832/10=83.2

Sum of the deviation = Zero (0)

4.Using the grades listed in question #3, calculate the range, variance, and standard deviation of the grade distribution. Briefly explain why it is important to square deviation scores in calculating the variance and standard deviation.

Grade | ||

100 | 16.8 | 282.24 |

78 | -5.2 | 27.04 |

89 | 5.8 | 33.64 |

92 | 8.8 | 77.44 |

55 | -28.2 | 759.24 |

90 | 6.8 | 46.24 |

80 | -3.2 | 10.24 |

65 | -18.2 | 331.24 |

88 | 4.8 | 23.04 |

95 | 11.8 | 139.24 |

**Range**

Range = Largest value – smallest value

=100- 55 = 45

**Variance**

Variance = (∑▒(X-X ̅ )^2 )/(n-1)=1765.60/9=196.1778

**Standard deviation
**

Standard deviation = √((∑▒(X-X ̅ )^2 )/(n-1))=√196.1778=14.006

Briefly explain why it is important to square deviation scores in calculating the variance and standard deviation

The reason for squaring the deviation scores in calculating the variance and standard deviation score is because squaring the deviation score always gives a positive value and so that the sum will not be equals to zero. In this exercise, the sum of the deviation is zero, therefore there is need to find the square of the deviation in calculating the variance and the standard deviation.